100(1-1/k^2)=36

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Solution for 100(1-1/k^2)=36 equation: 


D( k )

k^2 = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k in (-oo:0) U (0:+oo)

100*(1-(1/(k^2))) = 36 // - 36

100*(1-(1/(k^2)))-36 = 0

100*(1-k^-2)-36 = 0

100*(1-k^-2)-36 = 0

64-100*k^-2 = 0

64-100*k^-2 = 0

-100*k^-2 = -64 // : -100

k^-2 = 16/25

-2 < 0

1/(k^2) = 16/25 // * k^2

1 = 16/25*k^2 // : 16/25

25/16 = k^2

k^2 = 25/16 // ^ 1/2

abs(k) = 5/4

k = 5/4 or k = -5/4

k in { 5/4, -5/4 }

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